3v^{8}v^-8u^-4u*2x^9*7x^6 eching

$$3 v ^ { 8 } v ^ { - 8 } u ^ { - 4 } u \cdot 2 x ^ { 9 } \cdot 7 x ^ { 6 }$$

Baholash

$$\frac{42x^{15}}{u^{3}}$$

Yechim qadamlari

1 hosil qilish uchun v^{8} va v^{-8} ni ko'paytirish.

$$3u^{-4}u\times 2x^{9}\times 7x^{6}$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. -4 va 1 ni qo‘shib, -3 ni oling.

$$3u^{-3}\times 2x^{9}\times 7x^{6}$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 9 va 6 ni qo‘shib, 15 ni oling.

$$3u^{-3}\times 2x^{15}\times 7$$

6 hosil qilish uchun 3 va 2 ni ko'paytirish.

$$6u^{-3}x^{15}\times 7$$

42 hosil qilish uchun 6 va 7 ni ko'paytirish.

$$42u^{-3}x^{15}$$

x ga nisbatan hosilani topish

$$\frac{630x^{14}}{u^{3}}$$