3c^2+6c eching

$$3 c ^ { 2 } + 6 c$$

Omil

$$3c\left(c+2\right)$$

Yechim qadamlari

3 omili.

$$3\left(c^{2}+2c\right)$$

Hisoblang: c^{2}+2c. c omili.

$$c\left(c+2\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$3c\left(c+2\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$3c^{2}+6c=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$c=\frac{-6±\sqrt{6^{2}}}{2\times 3}$$

6^{2} ning kvadrat ildizini chiqarish.

$$c=\frac{-6±6}{2\times 3}$$

2 ni 3 marotabaga ko'paytirish.

$$c=\frac{-6±6}{6}$$

c=\frac{-6±6}{6} tenglamasini yeching, bunda ± musbat. -6 ni 6 ga qo'shish.

$$c=\frac{0}{6}$$

0 ni 6 ga bo'lish.

$$c=0$$

c=\frac{-6±6}{6} tenglamasini yeching, bunda ± manfiy. -6 dan 6 ni ayirish.

$$c=-\frac{12}{6}$$

-12 ni 6 ga bo'lish.

$$c=-2$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun -2 ga bo‘ling.

$$3c^{2}+6c=3c\left(c-\left(-2\right)\right)$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$3c^{2}+6c=3c\left(c+2\right)$$

Baholash

$$3c\left(c+2\right)$$