3b^{8}b^-8v^-4v*2x^9*7x^6 eching

$$3 b ^ { 8 } b ^ { - 8 } v ^ { - 4 } v \cdot 2 x ^ { 9 } \cdot 7 x ^ { 6 }$$

Baholash

$$\frac{42x^{15}}{v^{3}}$$

Yechim qadamlari

1 hosil qilish uchun b^{8} va b^{-8} ni ko'paytirish.

$$3v^{-4}v\times 2x^{9}\times 7x^{6}$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. -4 va 1 ni qo‘shib, -3 ni oling.

$$3v^{-3}\times 2x^{9}\times 7x^{6}$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 9 va 6 ni qo‘shib, 15 ni oling.

$$3v^{-3}\times 2x^{15}\times 7$$

6 hosil qilish uchun 3 va 2 ni ko'paytirish.

$$6v^{-3}x^{15}\times 7$$

42 hosil qilish uchun 6 va 7 ni ko'paytirish.

$$42v^{-3}x^{15}$$

x ga nisbatan hosilani topish

$$\frac{630x^{14}}{v^{3}}$$