3-sqrt{49}+2(3+4^2)div12 eching

$$3 - \sqrt { 49 } + 2 ( 3 + 4 ^ { 2 } ) \div 12$$

Baholash

$$-\frac{5}{6}\approx -0,833333333$$

Yechim qadamlari

49 ning kvadrat ildizini hisoblab, 7 natijaga ega bo‘ling.

$$3-7+\frac{2\left(3+4^{2}\right)}{12}$$

-4 olish uchun 3 dan 7 ni ayirish.

$$-4+\frac{2\left(3+4^{2}\right)}{12}$$

2 daraja ko‘rsatkichini 4 ga hisoblang va 16 ni qiymatni oling.

$$-4+\frac{2\left(3+16\right)}{12}$$

19 olish uchun 3 va 16'ni qo'shing.

$$-4+\frac{2\times 19}{12}$$

38 hosil qilish uchun 2 va 19 ni ko'paytirish.

$$-4+\frac{38}{12}$$

\frac{38}{12} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$-4+\frac{19}{6}$$

-4 ni -\frac{24}{6} kasrga o‘giring.

$$-\frac{24}{6}+\frac{19}{6}$$

-\frac{24}{6} va \frac{19}{6} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\frac{-24+19}{6}$$

-5 olish uchun -24 va 19'ni qo'shing.

$$-\frac{5}{6}$$

Omil

$$-\frac{5}{6} = -0,8333333333333334$$