3 - ∫ x^4 wrt x=3x^3/5+c eching

$$3 - \int x ^ { 4 } d x = \frac { 3 x ^ { 3 } } { 5 } + c$$

c uchun yechish

$$c=-\frac{x^{5}}{5}-\frac{3x^{3}}{5}-С+3$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 5 ga ko'paytirish.

$$15-5\int x^{4}\mathrm{d}x=3x^{3}+5c$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$3x^{3}+5c=15-5\int x^{4}\mathrm{d}x$$

Ikkala tarafdan 3x^{3} ni ayirish.

$$5c=15-5\int x^{4}\mathrm{d}x-3x^{3}$$

Tenglama standart shaklda.

$$5c=15-5С-3x^{3}-x^{5}$$

Ikki tarafini 5 ga bo‘ling.

$$\frac{5c}{5}=\frac{15-5С-3x^{3}-x^{5}}{5}$$

5 ga bo'lish 5 ga ko'paytirishni bekor qiladi.

$$c=\frac{15-5С-3x^{3}-x^{5}}{5}$$

15-x^{5}-5С-3x^{3} ni 5 ga bo'lish.

$$c=-\frac{x^{5}}{5}-\frac{3x^{3}}{5}-С+3$$