3 - ∫ x^4/3 wrt x=3x^3/3/5+c eching

$$3 - \int x ^ { 4 / 3 } d x = \frac { 3 x ^ { 3 / 3 } } { 5 } + c$$

c uchun yechish

$$c=-\frac{3x^{\frac{7}{3}}}{7}-\frac{3x}{5}-С+3$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 5 ga ko'paytirish.

$$15-5\int x^{\frac{4}{3}}\mathrm{d}x=3x^{\frac{3}{3}}+5c$$

1 ni olish uchun 3 ni 3 ga bo‘ling.

$$15-5\int x^{\frac{4}{3}}\mathrm{d}x=3x^{1}+5c$$

1 daraja ko‘rsatkichini x ga hisoblang va x ni qiymatni oling.

$$15-5\int x^{\frac{4}{3}}\mathrm{d}x=3x+5c$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$3x+5c=15-5\int x^{\frac{4}{3}}\mathrm{d}x$$

Ikkala tarafdan 3x ni ayirish.

$$5c=15-5\int x^{\frac{4}{3}}\mathrm{d}x-3x$$

Tenglama standart shaklda.

$$5c=-\frac{15x^{\frac{7}{3}}}{7}-3x-5С+15$$

Ikki tarafini 5 ga bo‘ling.

$$\frac{5c}{5}=\frac{-\frac{15x^{\frac{7}{3}}}{7}-3x-5С+15}{5}$$

5 ga bo'lish 5 ga ko'paytirishni bekor qiladi.

$$c=\frac{-\frac{15x^{\frac{7}{3}}}{7}-3x-5С+15}{5}$$

15-\frac{15x^{\frac{7}{3}}}{7}-5С-3x ni 5 ga bo'lish.

$$c=-\frac{3x^{\frac{7}{3}}}{7}-\frac{3x}{5}-С+3$$