3-2x-5/2leqx-1 eching

$$3 - \frac { 2 x - 5 } { 2 } \leq x - 1$$

x uchun yechish

$$x\geq \frac{13}{4}$$

Yechim qadamlari

Tenglamaning ikkala tarafini 2 ga ko'paytirish. 2 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$6-\left(2x-5\right)\leq 2x-2$$

2x-5 teskarisini topish uchun har birining teskarisini toping.

$$6-2x-\left(-5\right)\leq 2x-2$$

-5 ning teskarisi 5 ga teng.

$$6-2x+5\leq 2x-2$$

11 olish uchun 6 va 5'ni qo'shing.

$$11-2x\leq 2x-2$$

Ikkala tarafdan 2x ni ayirish.

$$11-2x-2x\leq -2$$

-4x ni olish uchun -2x va -2x ni birlashtirish.

$$11-4x\leq -2$$

Ikkala tarafdan 11 ni ayirish.

$$-4x\leq -2-11$$

-13 olish uchun -2 dan 11 ni ayirish.

$$-4x\leq -13$$

Ikki tarafini -4 ga bo‘ling. -4 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x\geq \frac{-13}{-4}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-13}{-4} kasrini \frac{13}{4} ga soddalashtirish mumkin.

$$x\geq \frac{13}{4}$$