3(x-4)^2=-6 eching

$$3 ( x - 4 ) ^ { 2 } = - 6$$

x uchun yechish (complex solution)

$$x=-\sqrt{2}i+4\approx 4-1,414213562i$$

$$x=4+\sqrt{2}i\approx 4+1,414213562i$$

Kvadrat ildizini topish bo'yicha qadamlar

3 ga bo'lish 3 ga ko'paytirishni bekor qiladi.

$$\left(x-4\right)^{2}=-\frac{6}{3}$$

-6 ni 3 ga bo'lish.

$$\left(x-4\right)^{2}=-2$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x-4=\sqrt{2}i x-4=-\sqrt{2}i$$

4 ni tenglamaning ikkala tarafiga qo'shish.

$$x-4-\left(-4\right)=\sqrt{2}i-\left(-4\right) x-4-\left(-4\right)=-\sqrt{2}i-\left(-4\right)$$

O‘zidan -4 ayirilsa 0 qoladi.

$$x=\sqrt{2}i-\left(-4\right) x=-\sqrt{2}i-\left(-4\right)$$

i\sqrt{2} dan -4 ni ayirish.

$$x=4+\sqrt{2}i$$

-i\sqrt{2} dan -4 ni ayirish.

$$x=-\sqrt{2}i+4$$

Tenglama yechildi.

$$x=4+\sqrt{2}i x=-\sqrt{2}i+4$$