3(x-1)+5leq5(x+2) eching

$$3 ( x - 1 ) + 5 \leq 5 ( x + 2 )$$

x uchun yechish

$$x\geq -4$$

Yechim qadamlari

3 ga x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x-3+5\leq 5\left(x+2\right)$$

2 olish uchun -3 va 5'ni qo'shing.

$$3x+2\leq 5\left(x+2\right)$$

5 ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x+2\leq 5x+10$$

Ikkala tarafdan 5x ni ayirish.

$$3x+2-5x\leq 10$$

-2x ni olish uchun 3x va -5x ni birlashtirish.

$$-2x+2\leq 10$$

Ikkala tarafdan 2 ni ayirish.

$$-2x\leq 10-2$$

8 olish uchun 10 dan 2 ni ayirish.

$$-2x\leq 8$$

Ikki tarafini -2 ga bo‘ling. -2 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x\geq \frac{8}{-2}$$

-4 ni olish uchun 8 ni -2 ga bo‘ling.

$$x\geq -4$$