3(x+2)^2+4=13 eching

$$3 ( x + 2 ) ^ { 2 } + 4 = 13$$

x uchun yechish

$$x=\sqrt{3}-2\approx -0,267949192$$

$$x=-\left(\sqrt{3}+2\right)\approx -3,732050808$$

Kvadrat ildizini topish bo'yicha qadamlar

Tenglamaning ikkala tarafidan 4 ni ayirish.

$$3\left(x+2\right)^{2}+4-4=13-4$$

O‘zidan 4 ayirilsa 0 qoladi.

$$3\left(x+2\right)^{2}=13-4$$

13 dan 4 ni ayirish.

$$3\left(x+2\right)^{2}=9$$

Ikki tarafini 3 ga bo‘ling.

$$\frac{3\left(x+2\right)^{2}}{3}=\frac{9}{3}$$

3 ga bo'lish 3 ga ko'paytirishni bekor qiladi.

$$\left(x+2\right)^{2}=\frac{9}{3}$$

9 ni 3 ga bo'lish.

$$\left(x+2\right)^{2}=3$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x+2=\sqrt{3} x+2=-\sqrt{3}$$

Tenglamaning ikkala tarafidan 2 ni ayirish.

$$x+2-2=\sqrt{3}-2 x+2-2=-\sqrt{3}-2$$

O‘zidan 2 ayirilsa 0 qoladi.

$$x=\sqrt{3}-2 x=-\sqrt{3}-2$$