3(x+1)geq5(x-1) eching

$$3 ( x + 1 ) \geq 5 ( x - 1 )$$

x uchun yechish

$$x\leq 4$$

Yechim qadamlari

3 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x+3\geq 5\left(x-1\right)$$

5 ga x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x+3\geq 5x-5$$

Ikkala tarafdan 5x ni ayirish.

$$3x+3-5x\geq -5$$

-2x ni olish uchun 3x va -5x ni birlashtirish.

$$-2x+3\geq -5$$

Ikkala tarafdan 3 ni ayirish.

$$-2x\geq -5-3$$

-8 olish uchun -5 dan 3 ni ayirish.

$$-2x\geq -8$$

Ikki tarafini -2 ga bo‘ling. -2 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x\leq \frac{-8}{-2}$$

4 ni olish uchun -8 ni -2 ga bo‘ling.

$$x\leq 4$$