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3\times 5^{3x+1}=36
Tenglamani yechish uchun eksponent va logaritmlarning qoidalaridan foydalanish.
5^{3x+1}=12
Ikki tarafini 3 ga bo‘ling.
\log(5^{3x+1})=\log(12)
Tenglamaning ikkala tarafiga tegishli logaritmni chiqarish.
\left(3x+1\right)\log(5)=\log(12)
Darajaga ko'tarigan logaritm raqami raqam logaritmining darajasidir.
3x+1=\frac{\log(12)}{\log(5)}
Ikki tarafini \log(5) ga bo‘ling.
3x+1=\log_{5}\left(12\right)
Asosiy tenglamani almashtirish orqali \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
3x=\log_{5}\left(12\right)-1
Tenglamaning ikkala tarafidan 1 ni ayirish.
x=\frac{\log_{5}\left(12\right)-1}{3}
Ikki tarafini 3 ga bo‘ling.