3(3y+1)<13y-8 eching

$$3 ( 3 y + 1 ) < 13 y - 8$$

y uchun yechish

$$y>\frac{11}{4}$$

Yechim qadamlari

3 ga 3y+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$9y+3<13y-8$$

Ikkala tarafdan 13y ni ayirish.

$$9y+3-13y<-8$$

-4y ni olish uchun 9y va -13y ni birlashtirish.

$$-4y+3<-8$$

Ikkala tarafdan 3 ni ayirish.

$$-4y<-8-3$$

-11 olish uchun -8 dan 3 ni ayirish.

$$-4y<-11$$

Ikki tarafini -4 ga bo‘ling. -4 <0 bo‘lganda, tengsizlikning yo‘nalishi o‘zgargan bo‘ladi.

$$y>\frac{-11}{-4}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-11}{-4} kasrini \frac{11}{4} ga soddalashtirish mumkin.

$$y>\frac{11}{4}$$