3(3x-1)=2(3x+2)(R:7/3) eching

$$3 ( 3 x - 1 ) = 2 ( 3 x + 2 ) ( R : 7 / 3 )$$

x uchun yechish

$$x=\frac{4R+7}{3\left(7-2R\right)}$$

$$R\neq \frac{7}{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

3 ga 3x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$9x-3=2\left(3x+2\right)\times \frac{R}{\frac{7}{3}}$$

2 ga 3x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$9x-3=\left(6x+4\right)\times \frac{R}{\frac{7}{3}}$$

6x+4 ga \frac{R}{\frac{7}{3}} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$9x-3=6x\times \frac{R}{\frac{7}{3}}+4\times \frac{R}{\frac{7}{3}}$$

Ikkala tarafdan 6x\times \frac{R}{\frac{7}{3}} ni ayirish.

$$9x-3-6x\times \frac{R}{\frac{7}{3}}=4\times \frac{R}{\frac{7}{3}}$$

3 ni ikki tarafga qo’shing.

$$9x-6x\times \frac{R}{\frac{7}{3}}=4\times \frac{R}{\frac{7}{3}}+3$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(9-6\times \frac{R}{\frac{7}{3}}\right)x=4\times \frac{R}{\frac{7}{3}}+3$$

Tenglama standart shaklda.

$$\left(-\frac{18R}{7}+9\right)x=\frac{12R}{7}+3$$

Ikki tarafini 9-\frac{18}{7}R ga bo‘ling.

$$\frac{\left(-\frac{18R}{7}+9\right)x}{-\frac{18R}{7}+9}=\frac{\frac{12R}{7}+3}{-\frac{18R}{7}+9}$$

9-\frac{18}{7}R ga bo'lish 9-\frac{18}{7}R ga ko'paytirishni bekor qiladi.

$$x=\frac{\frac{12R}{7}+3}{-\frac{18R}{7}+9}$$

\frac{12R}{7}+3 ni 9-\frac{18}{7}R ga bo'lish.

$$x=\frac{4R+7}{3\left(7-2R\right)}$$

R uchun yechish

$$R=-\frac{7\left(1-3x\right)}{2\left(3x+2\right)}$$

$$x\neq -\frac{2}{3}$$