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3x^{2}=6
6 ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.
x^{2}=\frac{6}{3}
Ikki tarafini 3 ga bo‘ling.
x^{2}=2
2 ni olish uchun 6 ni 3 ga bo‘ling.
x=\sqrt{2} x=-\sqrt{2}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
3x^{2}-6=0
Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 3\left(-6\right)}}{2\times 3}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 3 ni a, 0 ni b va -6 ni c bilan almashtiring.
x=\frac{0±\sqrt{-4\times 3\left(-6\right)}}{2\times 3}
0 kvadratini chiqarish.
x=\frac{0±\sqrt{-12\left(-6\right)}}{2\times 3}
-4 ni 3 marotabaga ko'paytirish.
x=\frac{0±\sqrt{72}}{2\times 3}
-12 ni -6 marotabaga ko'paytirish.
x=\frac{0±6\sqrt{2}}{2\times 3}
72 ning kvadrat ildizini chiqarish.
x=\frac{0±6\sqrt{2}}{6}
2 ni 3 marotabaga ko'paytirish.
x=\sqrt{2}
x=\frac{0±6\sqrt{2}}{6} tenglamasini yeching, bunda ± musbat.
x=-\sqrt{2}
x=\frac{0±6\sqrt{2}}{6} tenglamasini yeching, bunda ± manfiy.
x=\sqrt{2} x=-\sqrt{2}
Tenglama yechildi.