3x^2+12x eching

$$3 { x }^{ 2 } +12x$$

Omil

$$3x\left(x+4\right)$$

Yechim qadamlari

3 omili.

$$3\left(x^{2}+4x\right)$$

Hisoblang: x^{2}+4x. x omili.

$$x\left(x+4\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$3x\left(x+4\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$3x^{2}+12x=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-12±\sqrt{12^{2}}}{2\times 3}$$

12^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-12±12}{2\times 3}$$

2 ni 3 marotabaga ko'paytirish.

$$x=\frac{-12±12}{6}$$

x=\frac{-12±12}{6} tenglamasini yeching, bunda ± musbat. -12 ni 12 ga qo'shish.

$$x=\frac{0}{6}$$

0 ni 6 ga bo'lish.

$$x=0$$

x=\frac{-12±12}{6} tenglamasini yeching, bunda ± manfiy. -12 dan 12 ni ayirish.

$$x=-\frac{24}{6}$$

-24 ni 6 ga bo'lish.

$$x=-4$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun -4 ga bo‘ling.

$$3x^{2}+12x=3x\left(x-\left(-4\right)\right)$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$3x^{2}+12x=3x\left(x+4\right)$$

Baholash

$$3x\left(x+4\right)$$