3*(2-5x)-(4x-5)*(4x+5) eching

$$3 \cdot ( 2 - 5 x ) - ( 4 x - 5 ) \cdot ( 4 x + 5 )$$

Baholash

$$\left(1-x\right)\left(16x+31\right)$$

Yechim qadamlari

3 ga 2-5x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$6-15x-\left(4x-5\right)\left(4x+5\right)$$

Hisoblang: \left(4x-5\right)\left(4x+5\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$6-15x-\left(\left(4x\right)^{2}-5^{2}\right)$$

\left(4x\right)^{2} ni kengaytirish.

$$6-15x-\left(4^{2}x^{2}-5^{2}\right)$$

2 daraja ko‘rsatkichini 4 ga hisoblang va 16 ni qiymatni oling.

$$6-15x-\left(16x^{2}-5^{2}\right)$$

2 daraja ko‘rsatkichini 5 ga hisoblang va 25 ni qiymatni oling.

$$6-15x-\left(16x^{2}-25\right)$$

16x^{2}-25 teskarisini topish uchun har birining teskarisini toping.

$$6-15x-16x^{2}-\left(-25\right)$$

-25 ning teskarisi 25 ga teng.

$$6-15x-16x^{2}+25$$

31 olish uchun 6 va 25'ni qo'shing.

$$31-15x-16x^{2}$$

Kengaytirish

$$31-15x-16x^{2}$$

Yechim qadamlari

3 ga 2-5x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$6-15x-\left(4x-5\right)\left(4x+5\right)$$

Hisoblang: \left(4x-5\right)\left(4x+5\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$6-15x-\left(\left(4x\right)^{2}-5^{2}\right)$$

\left(4x\right)^{2} ni kengaytirish.

$$6-15x-\left(4^{2}x^{2}-5^{2}\right)$$

2 daraja ko‘rsatkichini 4 ga hisoblang va 16 ni qiymatni oling.

$$6-15x-\left(16x^{2}-5^{2}\right)$$

2 daraja ko‘rsatkichini 5 ga hisoblang va 25 ni qiymatni oling.

$$6-15x-\left(16x^{2}-25\right)$$

16x^{2}-25 teskarisini topish uchun har birining teskarisini toping.

$$6-15x-16x^{2}-\left(-25\right)$$

-25 ning teskarisi 25 ga teng.

$$6-15x-16x^{2}+25$$

31 olish uchun 6 va 25'ni qo'shing.

$$31-15x-16x^{2}$$