3^2+b^2=18 eching

$$3 ^ { 2 } + b ^ { 2 } = 18$$

b uchun yechish

$$b=-3$$

$$b=3$$

Kvadratlar farqidan foydalangan qadamlar

2 daraja ko‘rsatkichini 3 ga hisoblang va 9 ni qiymatni oling.

$$9+b^{2}=18$$

Ikkala tarafdan 18 ni ayirish.

$$9+b^{2}-18=0$$

-9 olish uchun 9 dan 18 ni ayirish.

$$-9+b^{2}=0$$

Hisoblang: -9+b^{2}. -9+b^{2} ni b^{2}-3^{2} sifatida qaytadan yozish. Kvadratlarning farqini ushbu formula bilan hisoblash mumkin: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(b-3\right)\left(b+3\right)=0$$

Tenglamani yechish uchun b-3=0 va b+3=0 ni yeching.

$$b=3 b=-3$$

Kvadrat ildizini topish bo'yicha qadamlar

2 daraja ko‘rsatkichini 3 ga hisoblang va 9 ni qiymatni oling.

$$9+b^{2}=18$$

Ikkala tarafdan 9 ni ayirish.

$$b^{2}=18-9$$

9 olish uchun 18 dan 9 ni ayirish.

$$b^{2}=9$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$b=3 b=-3$$

Kvadrat tenglamalaridan foydalanish qoidalari

2 daraja ko‘rsatkichini 3 ga hisoblang va 9 ni qiymatni oling.

$$9+b^{2}=18$$

Ikkala tarafdan 18 ni ayirish.

$$9+b^{2}-18=0$$

-9 olish uchun 9 dan 18 ni ayirish.

$$-9+b^{2}=0$$

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$b^{2}-9=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -9 ni c bilan almashtiring.

$$b=\frac{0±\sqrt{0^{2}-4\left(-9\right)}}{2}$$

0 kvadratini chiqarish.

$$b=\frac{0±\sqrt{-4\left(-9\right)}}{2}$$

-4 ni -9 marotabaga ko'paytirish.

$$b=\frac{0±\sqrt{36}}{2}$$

36 ning kvadrat ildizini chiqarish.

$$b=\frac{0±6}{2}$$

b=\frac{0±6}{2} tenglamasini yeching, bunda ± musbat. 6 ni 2 ga bo'lish.

$$b=3$$

b=\frac{0±6}{2} tenglamasini yeching, bunda ± manfiy. -6 ni 2 ga bo'lish.

$$b=-3$$

Tenglama yechildi.

$$b=3 b=-3$$