3^-p-2=27 eching

$$3 ^ { - p - 2 } = 27$$

p uchun yechish

$$p=-5$$

Logaritm ifodasidan foydalanish qadamlari

Tenglamani yechish uchun eksponent va logaritmlarning qoidalaridan foydalanish.

$$3^{-p-2}=27$$

Tenglamaning ikkala tarafiga tegishli logaritmni chiqarish.

$$\log(3^{-p-2})=\log(27)$$

Darajaga ko'tarigan logaritm raqami raqam logaritmining darajasidir.

$$\left(-p-2\right)\log(3)=\log(27)$$

Ikki tarafini \log(3) ga bo‘ling.

$$-p-2=\frac{\log(27)}{\log(3)}$$

Asosiy tenglamani almashtirish orqali \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$-p-2=\log_{3}\left(27\right)$$

2 ni tenglamaning ikkala tarafiga qo'shish.

$$-p=3-\left(-2\right)$$

Ikki tarafini -1 ga bo‘ling.

$$p=\frac{5}{-1}$$