2x+3+(y-1)4x-1=30x-4 eching

$$2x+3+(y-1)4x-1=30x-4$$

x uchun yechish

$$x=-\frac{3}{2\left(y-8\right)}$$

$$y\neq 8$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

y-1 ga 4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x+3+\left(4y-4\right)x-1=30x-4$$

4y-4 ga x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x+3+4yx-4x-1=30x-4$$

-2x ni olish uchun 2x va -4x ni birlashtirish.

$$-2x+3+4yx-1=30x-4$$

2 olish uchun 3 dan 1 ni ayirish.

$$-2x+2+4yx=30x-4$$

Ikkala tarafdan 30x ni ayirish.

$$-2x+2+4yx-30x=-4$$

-32x ni olish uchun -2x va -30x ni birlashtirish.

$$-32x+2+4yx=-4$$

Ikkala tarafdan 2 ni ayirish.

$$-32x+4yx=-4-2$$

-6 olish uchun -4 dan 2 ni ayirish.

$$-32x+4yx=-6$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(-32+4y\right)x=-6$$

Tenglama standart shaklda.

$$\left(4y-32\right)x=-6$$

Ikki tarafini 4y-32 ga bo‘ling.

$$\frac{\left(4y-32\right)x}{4y-32}=-\frac{6}{4y-32}$$

4y-32 ga bo'lish 4y-32 ga ko'paytirishni bekor qiladi.

$$x=-\frac{6}{4y-32}$$

-6 ni 4y-32 ga bo'lish.

$$x=-\frac{3}{2\left(y-8\right)}$$

y uchun yechish

$$y=8-\frac{3}{2x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

y-1 ga 4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x+3+\left(4y-4\right)x-1=30x-4$$

4y-4 ga x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x+3+4yx-4x-1=30x-4$$

-2x ni olish uchun 2x va -4x ni birlashtirish.

$$-2x+3+4yx-1=30x-4$$

2 olish uchun 3 dan 1 ni ayirish.

$$-2x+2+4yx=30x-4$$

2x ni ikki tarafga qo’shing.

$$2+4yx=30x-4+2x$$

32x ni olish uchun 30x va 2x ni birlashtirish.

$$2+4yx=32x-4$$

Ikkala tarafdan 2 ni ayirish.

$$4yx=32x-4-2$$

-6 olish uchun -4 dan 2 ni ayirish.

$$4yx=32x-6$$

Tenglama standart shaklda.

$$4xy=32x-6$$

Ikki tarafini 4x ga bo‘ling.

$$\frac{4xy}{4x}=\frac{32x-6}{4x}$$

4x ga bo'lish 4x ga ko'paytirishni bekor qiladi.

$$y=\frac{32x-6}{4x}$$

32x-6 ni 4x ga bo'lish.

$$y=8-\frac{3}{2x}$$