27+3+10+6^5x-6x+27geq10 eching

$$27 + 3 + 10 + 6 ^ { 5 } x - 6 x + 27 \geq 10$$

x uchun yechish

$$x\geq -\frac{19}{2590}$$

Yechim qadamlari

30 olish uchun 27 va 3'ni qo'shing.

$$30+10+6^{5}x-6x+27\geq 10$$

40 olish uchun 30 va 10'ni qo'shing.

$$40+6^{5}x-6x+27\geq 10$$

5 daraja ko‘rsatkichini 6 ga hisoblang va 7776 ni qiymatni oling.

$$40+7776x-6x+27\geq 10$$

7770x ni olish uchun 7776x va -6x ni birlashtirish.

$$40+7770x+27\geq 10$$

67 olish uchun 40 va 27'ni qo'shing.

$$67+7770x\geq 10$$

Ikkala tarafdan 67 ni ayirish.

$$7770x\geq 10-67$$

-57 olish uchun 10 dan 67 ni ayirish.

$$7770x\geq -57$$

Ikki tarafini 7770 ga bo‘ling. 7770 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$x\geq \frac{-57}{7770}$$

\frac{-57}{7770} ulushini 3 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x\geq -\frac{19}{2590}$$