25x-5x^2 eching

$$25 x - 5 x ^ { 2 }$$

Omil

$$5x\left(5-x\right)$$

Yechim qadamlari

5 omili.

$$5\left(5x-x^{2}\right)$$

Hisoblang: 5x-x^{2}. x omili.

$$x\left(5-x\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$5x\left(-x+5\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-5x^{2}+25x=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-25±\sqrt{25^{2}}}{2\left(-5\right)}$$

25^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-25±25}{2\left(-5\right)}$$

2 ni -5 marotabaga ko'paytirish.

$$x=\frac{-25±25}{-10}$$

x=\frac{-25±25}{-10} tenglamasini yeching, bunda ± musbat. -25 ni 25 ga qo'shish.

$$x=\frac{0}{-10}$$

0 ni -10 ga bo'lish.

$$x=0$$

x=\frac{-25±25}{-10} tenglamasini yeching, bunda ± manfiy. -25 dan 25 ni ayirish.

$$x=-\frac{50}{-10}$$

-50 ni -10 ga bo'lish.

$$x=5$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun 5 ga bo‘ling.

$$-5x^{2}+25x=-5x\left(x-5\right)$$

Baholash

$$5x\left(5-x\right)$$