25m/s=text{dam/}h eching

$$25 m / s = \text { dam / } h$$

a uchun yechish

$$\left\{\begin{matrix}a=\frac{25h}{ds}\text{, }&s\neq 0\text{ and }d\neq 0\text{ and }h\neq 0\\a\in \mathrm{R}\text{, }&m=0\text{ and }s\neq 0\text{ and }h\neq 0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini hs ga, s,h ning eng kichik karralisiga ko‘paytiring.

$$h\times 25m=sdam$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$sdam=h\times 25m$$

Tenglama standart shaklda.

$$dmsa=25hm$$

Ikki tarafini sdm ga bo‘ling.

$$\frac{dmsa}{dms}=\frac{25hm}{dms}$$

sdm ga bo'lish sdm ga ko'paytirishni bekor qiladi.

$$a=\frac{25hm}{dms}$$

25hm ni sdm ga bo'lish.

$$a=\frac{25h}{ds}$$

d uchun yechish

$$\left\{\begin{matrix}d=\frac{25h}{as}\text{, }&s\neq 0\text{ and }a\neq 0\text{ and }h\neq 0\\d\in \mathrm{R}\text{, }&m=0\text{ and }s\neq 0\text{ and }h\neq 0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini hs ga, s,h ning eng kichik karralisiga ko‘paytiring.

$$h\times 25m=sdam$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$sdam=h\times 25m$$

Tenglama standart shaklda.

$$amsd=25hm$$

Ikki tarafini sam ga bo‘ling.

$$\frac{amsd}{ams}=\frac{25hm}{ams}$$

sam ga bo'lish sam ga ko'paytirishni bekor qiladi.

$$d=\frac{25hm}{ams}$$

25hm ni sam ga bo'lish.

$$d=\frac{25h}{as}$$