25(1-x)^2=16 eching

$$25 ( 1 - x ) ^ { 2 } = 16$$

x uchun yechish

$$x=\frac{1}{5}=0,2$$

$$x = \frac{9}{5} = 1\frac{4}{5} = 1,8$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikki tarafini 25 ga bo‘ling.

$$\frac{25\left(-x+1\right)^{2}}{25}=\frac{16}{25}$$

25 ga bo'lish 25 ga ko'paytirishni bekor qiladi.

$$\left(-x+1\right)^{2}=\frac{16}{25}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$-x+1=\frac{4}{5} -x+1=-\frac{4}{5}$$

Tenglamaning ikkala tarafidan 1 ni ayirish.

$$-x+1-1=\frac{4}{5}-1 -x+1-1=-\frac{4}{5}-1$$

O‘zidan 1 ayirilsa 0 qoladi.

$$-x=\frac{4}{5}-1 -x=-\frac{4}{5}-1$$

\frac{4}{5} dan 1 ni ayirish.

$$-x=-\frac{1}{5}$$

-\frac{4}{5} dan 1 ni ayirish.

$$-x=-\frac{9}{5}$$

Ikki tarafini -1 ga bo‘ling.

$$\frac{-x}{-1}=-\frac{\frac{1}{5}}{-1} \frac{-x}{-1}=-\frac{\frac{9}{5}}{-1}$$

-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.

$$x=-\frac{\frac{1}{5}}{-1} x=-\frac{\frac{9}{5}}{-1}$$

-\frac{1}{5} ni -1 ga bo'lish.

$$x=\frac{1}{5}$$

-\frac{9}{5} ni -1 ga bo'lish.

$$x=\frac{9}{5}$$

Tenglama yechildi.

$$x=\frac{1}{5} x=\frac{9}{5}$$