25^2+[(6-3/4)div2]*2^5 eching

$$25 ^ { 2 } + [ ( 6 - \frac { 3 } { 4 } ) \div 2 ] \times 2 ^ { 5 }$$

Baholash

$$709$$

Yechim qadamlari

2 daraja ko‘rsatkichini 25 ga hisoblang va 625 ni qiymatni oling.

$$625+\frac{6-\frac{3}{4}}{2}\times 2^{5}$$

6 ni \frac{24}{4} kasrga o‘giring.

$$625+\frac{\frac{24}{4}-\frac{3}{4}}{2}\times 2^{5}$$

\frac{24}{4} va \frac{3}{4} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$625+\frac{\frac{24-3}{4}}{2}\times 2^{5}$$

21 olish uchun 24 dan 3 ni ayirish.

$$625+\frac{\frac{21}{4}}{2}\times 2^{5}$$

\frac{\frac{21}{4}}{2} ni yagona kasrga aylantiring.

$$625+\frac{21}{4\times 2}\times 2^{5}$$

8 hosil qilish uchun 4 va 2 ni ko'paytirish.

$$625+\frac{21}{8}\times 2^{5}$$

5 daraja ko‘rsatkichini 2 ga hisoblang va 32 ni qiymatni oling.

$$625+\frac{21}{8}\times 32$$

\frac{21}{8}\times 32 ni yagona kasrga aylantiring.

$$625+\frac{21\times 32}{8}$$

672 hosil qilish uchun 21 va 32 ni ko'paytirish.

$$625+\frac{672}{8}$$

84 ni olish uchun 672 ni 8 ga bo‘ling.

$$625+84$$

709 olish uchun 625 va 84'ni qo'shing.

$$709$$

Omil

$$709$$