240*(3/10+8/15) eching

$$240 \times ( \frac{ 3 }{ 10 } + \frac{ 8 }{ 15 } )$$

Baholash

$$200$$

Yechim qadamlari

10 va 15 ning eng kichik umumiy karralisi 30 ga teng. \frac{3}{10} va \frac{8}{15} ni 30 maxraj bilan kasrlarga aylantirib oling.

$$240\left(\frac{9}{30}+\frac{16}{30}\right)$$

\frac{9}{30} va \frac{16}{30} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$240\times \frac{9+16}{30}$$

25 olish uchun 9 va 16'ni qo'shing.

$$240\times \frac{25}{30}$$

\frac{25}{30} ulushini 5 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$240\times \frac{5}{6}$$

240\times \frac{5}{6} ni yagona kasrga aylantiring.

$$\frac{240\times 5}{6}$$

1200 hosil qilish uchun 240 va 5 ni ko'paytirish.

$$\frac{1200}{6}$$

200 ni olish uchun 1200 ni 6 ga bo‘ling.

$$200$$

Omil

$$2^{3}\times 5^{2}$$