24x^2+16xy+8=84 eching

$$24 { x }^{ 2 } +16xy+8=84$$

y uchun yechish

$$y=-\frac{3x}{2}+\frac{19}{4x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan 24x^{2} ni ayirish.

$$16xy+8=84-24x^{2}$$

Ikkala tarafdan 8 ni ayirish.

$$16xy=84-24x^{2}-8$$

76 olish uchun 84 dan 8 ni ayirish.

$$16xy=76-24x^{2}$$

Ikki tarafini 16x ga bo‘ling.

$$\frac{16xy}{16x}=\frac{76-24x^{2}}{16x}$$

16x ga bo'lish 16x ga ko'paytirishni bekor qiladi.

$$y=\frac{76-24x^{2}}{16x}$$

76-24x^{2} ni 16x ga bo'lish.

$$y=-\frac{3x}{2}+\frac{19}{4x}$$

x uchun yechish

$$x=\frac{\sqrt{4y^{2}+114}}{6}-\frac{y}{3}$$

$$x=-\frac{\sqrt{4y^{2}+114}}{6}-\frac{y}{3}$$