20^2=AD^2+12^2 eching

$$20 ^ { 2 } = A D ^ { 2 } + 12 ^ { 2 }$$

A uchun yechish

$$A=\frac{256}{D^{2}}$$

$$D\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 20 ga hisoblang va 400 ni qiymatni oling.

$$400=AD^{2}+12^{2}$$

2 daraja ko‘rsatkichini 12 ga hisoblang va 144 ni qiymatni oling.

$$400=AD^{2}+144$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$AD^{2}+144=400$$

Ikkala tarafdan 144 ni ayirish.

$$AD^{2}=400-144$$

256 olish uchun 400 dan 144 ni ayirish.

$$AD^{2}=256$$

Tenglama standart shaklda.

$$D^{2}A=256$$

Ikki tarafini D^{2} ga bo‘ling.

$$\frac{D^{2}A}{D^{2}}=\frac{256}{D^{2}}$$

D^{2} ga bo'lish D^{2} ga ko'paytirishni bekor qiladi.

$$A=\frac{256}{D^{2}}$$

D uchun yechish (complex solution)

$$D=-16A^{-\frac{1}{2}}$$

$$D=16A^{-\frac{1}{2}}\text{, }A\neq 0$$

D uchun yechish

$$D=\frac{16}{\sqrt{A}}$$

$$D=-\frac{16}{\sqrt{A}}\text{, }A>0$$