2(3x(2-4)+2x-5(x+1))=-28 eching

$$2(3x(2-4)+2x-5(x+1))=-28$$

x uchun yechish

$$x=1$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikki tarafini 2 ga bo‘ling.

$$3x\left(2-4\right)+2x-5\left(x+1\right)=\frac{-28}{2}$$

-14 ni olish uchun -28 ni 2 ga bo‘ling.

$$3x\left(2-4\right)+2x-5\left(x+1\right)=-14$$

-2 olish uchun 2 dan 4 ni ayirish.

$$3x\left(-2\right)+2x-5\left(x+1\right)=-14$$

-6 hosil qilish uchun 3 va -2 ni ko'paytirish.

$$-6x+2x-5\left(x+1\right)=-14$$

-4x ni olish uchun -6x va 2x ni birlashtirish.

$$-4x-5\left(x+1\right)=-14$$

-5 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-4x-5x-5=-14$$

-9x ni olish uchun -4x va -5x ni birlashtirish.

$$-9x-5=-14$$

5 ni ikki tarafga qo’shing.

$$-9x=-14+5$$

-9 olish uchun -14 va 5'ni qo'shing.

$$-9x=-9$$

Ikki tarafini -9 ga bo‘ling.

$$x=\frac{-9}{-9}$$

1 ni olish uchun -9 ni -9 ga bo‘ling.

$$x=1$$