2(2+2x)+3+x+4+2x-6=0 eching

$$2(2+2x)+3+x+4+2x-6=0$$

x uchun yechish

$$x=-\frac{5}{7}\approx -0,714285714$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 ga 2+2x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4+4x+3+x+4+2x-6=0$$

7 olish uchun 4 va 3'ni qo'shing.

$$7+4x+x+4+2x-6=0$$

5x ni olish uchun 4x va x ni birlashtirish.

$$7+5x+4+2x-6=0$$

11 olish uchun 7 va 4'ni qo'shing.

$$11+5x+2x-6=0$$

7x ni olish uchun 5x va 2x ni birlashtirish.

$$11+7x-6=0$$

5 olish uchun 11 dan 6 ni ayirish.

$$5+7x=0$$

Ikkala tarafdan 5 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$7x=-5$$

Ikki tarafini 7 ga bo‘ling.

$$x=\frac{-5}{7}$$

\frac{-5}{7} kasri manfiy belgini olib tashlash bilan -\frac{5}{7} sifatida qayta yozilishi mumkin.

$$x=-\frac{5}{7}$$