2y1(x-1/3)-sqrt{2}=0 eching

$$2 y 1 ( x - \frac { 1 } { 3 } ) - \sqrt { 2 } = 0$$

x uchun yechish

$$x=\frac{1}{3}+\frac{\sqrt{2}}{2y_{1}}$$

$$y_{1}\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2y_{1} ga x-\frac{1}{3} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2y_{1}x-\frac{2}{3}y_{1}-\sqrt{2}=0$$

\frac{2}{3}y_{1} ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.

$$2y_{1}x-\sqrt{2}=\frac{2}{3}y_{1}$$

\sqrt{2} ni ikki tarafga qo’shing.

$$2y_{1}x=\frac{2}{3}y_{1}+\sqrt{2}$$

Tenglama standart shaklda.

$$2y_{1}x=\frac{2y_{1}}{3}+\sqrt{2}$$

Ikki tarafini 2y_{1} ga bo‘ling.

$$\frac{2y_{1}x}{2y_{1}}=\frac{\frac{2y_{1}}{3}+\sqrt{2}}{2y_{1}}$$

2y_{1} ga bo'lish 2y_{1} ga ko'paytirishni bekor qiladi.

$$x=\frac{\frac{2y_{1}}{3}+\sqrt{2}}{2y_{1}}$$

\frac{2y_{1}}{3}+\sqrt{2} ni 2y_{1} ga bo'lish.

$$x=\frac{1}{3}+\frac{\sqrt{2}}{2y_{1}}$$

y_1 uchun yechish

$$y_{1}=\frac{3\sqrt{2}}{2\left(3x-1\right)}$$

$$x\neq \frac{1}{3}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2y_{1} ga x-\frac{1}{3} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2y_{1}x-\frac{2}{3}y_{1}-\sqrt{2}=0$$

\sqrt{2} ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.

$$2y_{1}x-\frac{2}{3}y_{1}=\sqrt{2}$$

y_{1}'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(2x-\frac{2}{3}\right)y_{1}=\sqrt{2}$$

Ikki tarafini 2x-\frac{2}{3} ga bo‘ling.

$$\frac{\left(2x-\frac{2}{3}\right)y_{1}}{2x-\frac{2}{3}}=\frac{\sqrt{2}}{2x-\frac{2}{3}}$$

2x-\frac{2}{3} ga bo'lish 2x-\frac{2}{3} ga ko'paytirishni bekor qiladi.

$$y_{1}=\frac{\sqrt{2}}{2x-\frac{2}{3}}$$

\sqrt{2} ni 2x-\frac{2}{3} ga bo'lish.

$$y_{1}=\frac{3\sqrt{2}}{2\left(3x-1\right)}$$