2y*8u^7*2y^2u^8 eching

$$2 y \cdot 8 u ^ { 7 } \cdot 2 y ^ { 2 } u ^ { 8 }$$

Baholash

$$32y^{3}u^{15}$$

Yechim qadamlari

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 1 va 2 ni qo‘shib, 3 ni oling.

$$2y^{3}\times 8u^{7}\times 2u^{8}$$

Ayni asosning daraja ko‘rsatkichlarini ko‘paytirish uchun ularning darajalarini qo‘shing. 7 va 8 ni qo‘shib, 15 ni oling.

$$2y^{3}\times 8u^{15}\times 2$$

16 hosil qilish uchun 2 va 8 ni ko'paytirish.

$$16y^{3}u^{15}\times 2$$

32 hosil qilish uchun 16 va 2 ni ko'paytirish.

$$32y^{3}u^{15}$$

y ga nisbatan hosilani topish

$$96y^{2}u^{15}$$