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2x^{2}=3
3 ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.
x^{2}=\frac{3}{2}
Ikki tarafini 2 ga bo‘ling.
x=\frac{\sqrt{6}}{2} x=-\frac{\sqrt{6}}{2}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
2x^{2}-3=0
Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 2\left(-3\right)}}{2\times 2}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 2 ni a, 0 ni b va -3 ni c bilan almashtiring.
x=\frac{0±\sqrt{-4\times 2\left(-3\right)}}{2\times 2}
0 kvadratini chiqarish.
x=\frac{0±\sqrt{-8\left(-3\right)}}{2\times 2}
-4 ni 2 marotabaga ko'paytirish.
x=\frac{0±\sqrt{24}}{2\times 2}
-8 ni -3 marotabaga ko'paytirish.
x=\frac{0±2\sqrt{6}}{2\times 2}
24 ning kvadrat ildizini chiqarish.
x=\frac{0±2\sqrt{6}}{4}
2 ni 2 marotabaga ko'paytirish.
x=\frac{\sqrt{6}}{2}
x=\frac{0±2\sqrt{6}}{4} tenglamasini yeching, bunda ± musbat.
x=-\frac{\sqrt{6}}{2}
x=\frac{0±2\sqrt{6}}{4} tenglamasini yeching, bunda ± manfiy.
x=\frac{\sqrt{6}}{2} x=-\frac{\sqrt{6}}{2}
Tenglama yechildi.