2x^2=743 eching

$$2 x ^ { 2 } = 743$$

x uchun yechish

$$x = \frac{\sqrt{1486}}{2} \approx 19,274335267$$

$$x = -\frac{\sqrt{1486}}{2} \approx -19,274335267$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikki tarafini 2 ga bo‘ling.

$$x^{2}=\frac{743}{2}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\frac{\sqrt{1486}}{2} x=-\frac{\sqrt{1486}}{2}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikki tarafini 2 ga bo‘ling.

$$x^{2}=\frac{743}{2}$$

Ikkala tarafdan \frac{743}{2} ni ayirish.

$$x^{2}-\frac{743}{2}=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -\frac{743}{2} ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{743}{2}\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-\frac{743}{2}\right)}}{2}$$

-4 ni -\frac{743}{2} marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{1486}}{2}$$

x=\frac{0±\sqrt{1486}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\frac{\sqrt{1486}}{2}$$

x=\frac{0±\sqrt{1486}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\frac{\sqrt{1486}}{2}$$

Tenglama yechildi.

$$x=\frac{\sqrt{1486}}{2} x=-\frac{\sqrt{1486}}{2}$$