2x^2+xy=-16 eching

$$2 x ^ { 2 } + x y = - 16$$

y uchun yechish

$$y=-2x-\frac{16}{x}$$

$$x\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan 2x^{2} ni ayirish.

$$xy=-16-2x^{2}$$

Tenglama standart shaklda.

$$xy=-2x^{2}-16$$

Ikki tarafini x ga bo‘ling.

$$\frac{xy}{x}=\frac{-2x^{2}-16}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$y=\frac{-2x^{2}-16}{x}$$

-16-2x^{2} ni x ga bo'lish.

$$y=-2x-\frac{16}{x}$$

x uchun yechish (complex solution)

$$x=\frac{\sqrt{y^{2}-128}-y}{4}$$

$$x=\frac{-\sqrt{y^{2}-128}-y}{4}$$

x uchun yechish

$$x=\frac{\sqrt{y^{2}-128}-y}{4}$$

$$x=\frac{-\sqrt{y^{2}-128}-y}{4}\text{, }|y|\geq 8\sqrt{2}$$