2x^2+8x-y+8=0 eching

$$2 x ^ { 2 } + 8 x - y + 8 = 0$$

y uchun yechish

$$y=2\left(x+2\right)^{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan 2x^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$8x-y+8=-2x^{2}$$

Ikkala tarafdan 8x ni ayirish.

$$-y+8=-2x^{2}-8x$$

Ikkala tarafdan 8 ni ayirish.

$$-y=-2x^{2}-8x-8$$

Ikki tarafini -1 ga bo‘ling.

$$\frac{-y}{-1}=-\frac{2\left(x+2\right)^{2}}{-1}$$

-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.

$$y=-\frac{2\left(x+2\right)^{2}}{-1}$$

-2\left(2+x\right)^{2} ni -1 ga bo'lish.

$$y=2\left(x+2\right)^{2}$$

x uchun yechish (complex solution)

$$x=\frac{\sqrt{2y}}{2}-2$$

$$x=-\frac{\sqrt{2y}}{2}-2$$

x uchun yechish

$$x=\frac{\sqrt{2y}}{2}-2$$

$$x=-\frac{\sqrt{2y}}{2}-2\text{, }y\geq 0$$