2x^2+5=80 eching

$$2 x ^ { 2 } + 5 = 80$$

x uchun yechish

$$x = \frac{5 \sqrt{6}}{2} \approx 6,123724357$$

$$x = -\frac{5 \sqrt{6}}{2} \approx -6,123724357$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 5 ni ayirish.

$$2x^{2}=80-5$$

75 olish uchun 80 dan 5 ni ayirish.

$$2x^{2}=75$$

Ikki tarafini 2 ga bo‘ling.

$$x^{2}=\frac{75}{2}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\frac{5\sqrt{6}}{2} x=-\frac{5\sqrt{6}}{2}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 80 ni ayirish.

$$2x^{2}+5-80=0$$

-75 olish uchun 5 dan 80 ni ayirish.

$$2x^{2}-75=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 2 ni a, 0 ni b va -75 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 2\left(-75\right)}}{2\times 2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 2\left(-75\right)}}{2\times 2}$$

-4 ni 2 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-8\left(-75\right)}}{2\times 2}$$

-8 ni -75 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{600}}{2\times 2}$$

600 ning kvadrat ildizini chiqarish.

$$x=\frac{0±10\sqrt{6}}{2\times 2}$$

2 ni 2 marotabaga ko'paytirish.

$$x=\frac{0±10\sqrt{6}}{4}$$

x=\frac{0±10\sqrt{6}}{4} tenglamasini yeching, bunda ± musbat.

$$x=\frac{5\sqrt{6}}{2}$$

x=\frac{0±10\sqrt{6}}{4} tenglamasini yeching, bunda ± manfiy.

$$x=-\frac{5\sqrt{6}}{2}$$

Tenglama yechildi.

$$x=\frac{5\sqrt{6}}{2} x=-\frac{5\sqrt{6}}{2}$$