2x^2+4x-3 eching

$$2 x ^ { 2 } + 4 x - 3$$

Omil

$$2\left(x-\left(-\frac{\sqrt{10}}{2}-1\right)\right)\left(x-\left(\frac{\sqrt{10}}{2}-1\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$2x^{2}+4x-3=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-4±\sqrt{4^{2}-4\times 2\left(-3\right)}}{2\times 2}$$

4 kvadratini chiqarish.

$$x=\frac{-4±\sqrt{16-4\times 2\left(-3\right)}}{2\times 2}$$

-4 ni 2 marotabaga ko'paytirish.

$$x=\frac{-4±\sqrt{16-8\left(-3\right)}}{2\times 2}$$

-8 ni -3 marotabaga ko'paytirish.

$$x=\frac{-4±\sqrt{16+24}}{2\times 2}$$

16 ni 24 ga qo'shish.

$$x=\frac{-4±\sqrt{40}}{2\times 2}$$

40 ning kvadrat ildizini chiqarish.

$$x=\frac{-4±2\sqrt{10}}{2\times 2}$$

2 ni 2 marotabaga ko'paytirish.

$$x=\frac{-4±2\sqrt{10}}{4}$$

x=\frac{-4±2\sqrt{10}}{4} tenglamasini yeching, bunda ± musbat. -4 ni 2\sqrt{10} ga qo'shish.

$$x=\frac{2\sqrt{10}-4}{4}$$

-4+2\sqrt{10} ni 4 ga bo'lish.

$$x=\frac{\sqrt{10}}{2}-1$$

x=\frac{-4±2\sqrt{10}}{4} tenglamasini yeching, bunda ± manfiy. -4 dan 2\sqrt{10} ni ayirish.

$$x=\frac{-2\sqrt{10}-4}{4}$$

-4-2\sqrt{10} ni 4 ga bo'lish.

$$x=-\frac{\sqrt{10}}{2}-1$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun -1+\frac{\sqrt{10}}{2} ga va x_{2} uchun -1-\frac{\sqrt{10}}{2} ga bo‘ling.

$$2x^{2}+4x-3=2\left(x-\left(\frac{\sqrt{10}}{2}-1\right)\right)\left(x-\left(-\frac{\sqrt{10}}{2}-1\right)\right)$$

Baholash

$$2x^{2}+4x-3$$