2x^2+3x+2y=10 eching

$$2 x ^ { 2 } + 3 x + 2 y = 10$$

y uchun yechish

$$y=-x^{2}-\frac{3x}{2}+5$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan 2x^{2} ni ayirish.

$$3x+2y=10-2x^{2}$$

Ikkala tarafdan 3x ni ayirish.

$$2y=10-2x^{2}-3x$$

Tenglama standart shaklda.

$$2y=10-3x-2x^{2}$$

Ikki tarafini 2 ga bo‘ling.

$$\frac{2y}{2}=\frac{10-3x-2x^{2}}{2}$$

2 ga bo'lish 2 ga ko'paytirishni bekor qiladi.

$$y=\frac{10-3x-2x^{2}}{2}$$

10-2x^{2}-3x ni 2 ga bo'lish.

$$y=-x^{2}-\frac{3x}{2}+5$$

x uchun yechish (complex solution)

$$x=\frac{\sqrt{89-16y}-3}{4}$$

$$x=\frac{-\sqrt{89-16y}-3}{4}$$

x uchun yechish

$$x=\frac{\sqrt{89-16y}-3}{4}$$

$$x=\frac{-\sqrt{89-16y}-3}{4}\text{, }y\leq \frac{89}{16}$$