2x^2+12x eching

$$2 x ^ { 2 } + 12 x$$

Omil

$$2x\left(x+6\right)$$

Yechim qadamlari

2 omili.

$$2\left(x^{2}+6x\right)$$

Hisoblang: x^{2}+6x. x omili.

$$x\left(x+6\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$2x\left(x+6\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$2x^{2}+12x=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-12±\sqrt{12^{2}}}{2\times 2}$$

12^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-12±12}{2\times 2}$$

2 ni 2 marotabaga ko'paytirish.

$$x=\frac{-12±12}{4}$$

x=\frac{-12±12}{4} tenglamasini yeching, bunda ± musbat. -12 ni 12 ga qo'shish.

$$x=\frac{0}{4}$$

0 ni 4 ga bo'lish.

$$x=0$$

x=\frac{-12±12}{4} tenglamasini yeching, bunda ± manfiy. -12 dan 12 ni ayirish.

$$x=-\frac{24}{4}$$

-24 ni 4 ga bo'lish.

$$x=-6$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun -6 ga bo‘ling.

$$2x^{2}+12x=2x\left(x-\left(-6\right)\right)$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$2x^{2}+12x=2x\left(x+6\right)$$

Baholash

$$2x\left(x+6\right)$$