2x+3+4x^2-5x+6 eching

$$2 x + 3 + 4 x ^ { 2 } - 5 x + 6$$

Baholash

$$4x^{2}-3x+9$$

Yechim qadamlari

-3x ni olish uchun 2x va -5x ni birlashtirish.

$$-3x+3+4x^{2}+6$$

9 olish uchun 3 va 6'ni qo'shing.

$$-3x+9+4x^{2}$$

x ga nisbatan hosilani topish

$$8x-3$$

Yig'indi uchun derivativ qoidasidan foydalanish qadamlari

-3x ni olish uchun 2x va -5x ni birlashtirish.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3x+3+4x^{2}+6)$$

9 olish uchun 3 va 6'ni qo'shing.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3x+9+4x^{2})$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$-3x^{1-1}+2\times 4x^{2-1}$$

1 dan 1 ni ayirish.

$$-3x^{0}+2\times 4x^{2-1}$$

2 ni 4 marotabaga ko'paytirish.

$$-3x^{0}+8x^{2-1}$$

2 dan 1 ni ayirish.

$$-3x^{0}+8x^{1}$$

Har qanday t sharti uchun t^{1}=t.

$$-3x^{0}+8x$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$-3+8x$$