2s^3-27-18s+3s^2 eching

$$2 s ^ { 3 } - 27 - 18 s + 3 s ^ { 2 }$$

Omil

$$\left(s-3\right)\left(s+3\right)\left(2s+3\right)$$

Yechim qadamlari

2s^{3}-27-18s+3s^{2}=\left(2s^{3}+3s^{2}\right)+\left(-18s-27\right) misolini guruhlang hamda s^{2} ni birinchi va -9 ni ikkinchi guruhdan ajrating.

$$s^{2}\left(2s+3\right)-9\left(2s+3\right)$$

Distributiv funktsiyasidan foydalangan holda 2s+3 umumiy terminini chiqaring.

$$\left(2s+3\right)\left(s^{2}-9\right)$$

Hisoblang: s^{2}-9. s^{2}-9 ni s^{2}-3^{2} sifatida qaytadan yozish. Kvadratlarning farqini ushbu formula bilan hisoblash mumkin: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(s-3\right)\left(s+3\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$\left(s-3\right)\left(s+3\right)\left(2s+3\right)$$

Baholash

$$\left(2s+3\right)\left(s^{2}-9\right)$$