2s^2-6s eching

$$2 s ^ { 2 } - 6 s$$

Omil

$$2s\left(s-3\right)$$

Yechim qadamlari

2 omili.

$$2\left(s^{2}-3s\right)$$

Hisoblang: s^{2}-3s. s omili.

$$s\left(s-3\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$2s\left(s-3\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$2s^{2}-6s=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$s=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}}}{2\times 2}$$

\left(-6\right)^{2} ning kvadrat ildizini chiqarish.

$$s=\frac{-\left(-6\right)±6}{2\times 2}$$

-6 ning teskarisi 6 ga teng.

$$s=\frac{6±6}{2\times 2}$$

2 ni 2 marotabaga ko'paytirish.

$$s=\frac{6±6}{4}$$

s=\frac{6±6}{4} tenglamasini yeching, bunda ± musbat. 6 ni 6 ga qo'shish.

$$s=\frac{12}{4}$$

12 ni 4 ga bo'lish.

$$s=3$$

s=\frac{6±6}{4} tenglamasini yeching, bunda ± manfiy. 6 dan 6 ni ayirish.

$$s=\frac{0}{4}$$

0 ni 4 ga bo'lish.

$$s=0$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 3 ga va x_{2} uchun 0 ga bo‘ling.

$$2s^{2}-6s=2\left(s-3\right)s$$

Baholash

$$2s\left(s-3\right)$$