2h^2-3h-18 eching

$$2 h ^ { 2 } - 3 h - 18$$

Omil

$$2\left(h-\frac{3-3\sqrt{17}}{4}\right)\left(h-\frac{3\sqrt{17}+3}{4}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$2h^{2}-3h-18=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$h=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}-4\times 2\left(-18\right)}}{2\times 2}$$

-3 kvadratini chiqarish.

$$h=\frac{-\left(-3\right)±\sqrt{9-4\times 2\left(-18\right)}}{2\times 2}$$

-4 ni 2 marotabaga ko'paytirish.

$$h=\frac{-\left(-3\right)±\sqrt{9-8\left(-18\right)}}{2\times 2}$$

-8 ni -18 marotabaga ko'paytirish.

$$h=\frac{-\left(-3\right)±\sqrt{9+144}}{2\times 2}$$

9 ni 144 ga qo'shish.

$$h=\frac{-\left(-3\right)±\sqrt{153}}{2\times 2}$$

153 ning kvadrat ildizini chiqarish.

$$h=\frac{-\left(-3\right)±3\sqrt{17}}{2\times 2}$$

-3 ning teskarisi 3 ga teng.

$$h=\frac{3±3\sqrt{17}}{2\times 2}$$

2 ni 2 marotabaga ko'paytirish.

$$h=\frac{3±3\sqrt{17}}{4}$$

h=\frac{3±3\sqrt{17}}{4} tenglamasini yeching, bunda ± musbat. 3 ni 3\sqrt{17} ga qo'shish.

$$h=\frac{3\sqrt{17}+3}{4}$$

h=\frac{3±3\sqrt{17}}{4} tenglamasini yeching, bunda ± manfiy. 3 dan 3\sqrt{17} ni ayirish.

$$h=\frac{3-3\sqrt{17}}{4}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{3+3\sqrt{17}}{4} ga va x_{2} uchun \frac{3-3\sqrt{17}}{4} ga bo‘ling.

$$2h^{2}-3h-18=2\left(h-\frac{3\sqrt{17}+3}{4}\right)\left(h-\frac{3-3\sqrt{17}}{4}\right)$$

Baholash

$$2h^{2}-3h-18$$