2-3x_{4}=-1/8x-3 eching

$$2 - 3 x _ { 4 } = - 1 / 8 x - 3$$

x uchun yechish

$$x=24x_{4}-40$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$-\frac{1}{8}x-3=2-3x_{4}$$

3 ni ikki tarafga qo’shing.

$$-\frac{1}{8}x=2-3x_{4}+3$$

5 olish uchun 2 va 3'ni qo'shing.

$$-\frac{1}{8}x=5-3x_{4}$$

Ikkala tarafini -8 ga ko‘paytiring.

$$\frac{-\frac{1}{8}x}{-\frac{1}{8}}=\frac{5-3x_{4}}{-\frac{1}{8}}$$

-\frac{1}{8} ga bo'lish -\frac{1}{8} ga ko'paytirishni bekor qiladi.

$$x=\frac{5-3x_{4}}{-\frac{1}{8}}$$

5-3x_{4} ni -\frac{1}{8} ga bo'lish 5-3x_{4} ga k'paytirish -\frac{1}{8} ga qaytarish.

$$x=24x_{4}-40$$

x_4 uchun yechish

$$x_{4}=\frac{x+40}{24}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan 2 ni ayirish.

$$-3x_{4}=-\frac{1}{8}x-3-2$$

-5 olish uchun -3 dan 2 ni ayirish.

$$-3x_{4}=-\frac{1}{8}x-5$$

Tenglama standart shaklda.

$$-3x_{4}=-\frac{x}{8}-5$$

Ikki tarafini -3 ga bo‘ling.

$$\frac{-3x_{4}}{-3}=\frac{-\frac{x}{8}-5}{-3}$$

-3 ga bo'lish -3 ga ko'paytirishni bekor qiladi.

$$x_{4}=\frac{-\frac{x}{8}-5}{-3}$$

-\frac{x}{8}-5 ni -3 ga bo'lish.

$$x_{4}=\frac{x}{24}+\frac{5}{3}$$