2(x-3)^2-3(x+1)^2 eching

$$2 ( x - 3 ) ^ { 2 } - 3 ( x + 1 ) ^ { 2 }$$

Baholash

$$15-18x-x^{2}$$

Yechim qadamlari

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(x-3\right)^{2} kengaytirilishi uchun ishlating.

$$2\left(x^{2}-6x+9\right)-3\left(x+1\right)^{2}$$

2 ga x^{2}-6x+9 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x^{2}-12x+18-3\left(x+1\right)^{2}$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+1\right)^{2} kengaytirilishi uchun ishlating.

$$2x^{2}-12x+18-3\left(x^{2}+2x+1\right)$$

-3 ga x^{2}+2x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x^{2}-12x+18-3x^{2}-6x-3$$

-x^{2} ni olish uchun 2x^{2} va -3x^{2} ni birlashtirish.

$$-x^{2}-12x+18-6x-3$$

-18x ni olish uchun -12x va -6x ni birlashtirish.

$$-x^{2}-18x+18-3$$

15 olish uchun 18 dan 3 ni ayirish.

$$-x^{2}-18x+15$$

Kengaytirish

$$15-18x-x^{2}$$

Yechim qadamlari

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(x-3\right)^{2} kengaytirilishi uchun ishlating.

$$2\left(x^{2}-6x+9\right)-3\left(x+1\right)^{2}$$

2 ga x^{2}-6x+9 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x^{2}-12x+18-3\left(x+1\right)^{2}$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+1\right)^{2} kengaytirilishi uchun ishlating.

$$2x^{2}-12x+18-3\left(x^{2}+2x+1\right)$$

-3 ga x^{2}+2x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x^{2}-12x+18-3x^{2}-6x-3$$

-x^{2} ni olish uchun 2x^{2} va -3x^{2} ni birlashtirish.

$$-x^{2}-12x+18-6x-3$$

-18x ni olish uchun -12x va -6x ni birlashtirish.

$$-x^{2}-18x+18-3$$

15 olish uchun 18 dan 3 ni ayirish.

$$-x^{2}-18x+15$$