2(x-1)^2-1(x+1)^2 eching

$$2 ( x - 1 ) ^ { 2 } - 1 ( x + 1 ) ^ { 2 }$$

Baholash

$$x^{2}-6x+1$$

Yechim qadamlari

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(x-1\right)^{2} kengaytirilishi uchun ishlating.

$$2\left(x^{2}-2x+1\right)-1\left(x+1\right)^{2}$$

2 ga x^{2}-2x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x^{2}-4x+2-1\left(x+1\right)^{2}$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+1\right)^{2} kengaytirilishi uchun ishlating.

$$2x^{2}-4x+2-\left(x^{2}+2x+1\right)$$

x^{2}+2x+1 teskarisini topish uchun har birining teskarisini toping.

$$2x^{2}-4x+2-x^{2}-2x-1$$

x^{2} ni olish uchun 2x^{2} va -x^{2} ni birlashtirish.

$$x^{2}-4x+2-2x-1$$

-6x ni olish uchun -4x va -2x ni birlashtirish.

$$x^{2}-6x+2-1$$

1 olish uchun 2 dan 1 ni ayirish.

$$x^{2}-6x+1$$

Kengaytirish

$$x^{2}-6x+1$$

Yechim qadamlari

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(x-1\right)^{2} kengaytirilishi uchun ishlating.

$$2\left(x^{2}-2x+1\right)-1\left(x+1\right)^{2}$$

2 ga x^{2}-2x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2x^{2}-4x+2-1\left(x+1\right)^{2}$$

\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+1\right)^{2} kengaytirilishi uchun ishlating.

$$2x^{2}-4x+2-\left(x^{2}+2x+1\right)$$

x^{2}+2x+1 teskarisini topish uchun har birining teskarisini toping.

$$2x^{2}-4x+2-x^{2}-2x-1$$

x^{2} ni olish uchun 2x^{2} va -x^{2} ni birlashtirish.

$$x^{2}-4x+2-2x-1$$

-6x ni olish uchun -4x va -2x ni birlashtirish.

$$x^{2}-6x+2-1$$

1 olish uchun 2 dan 1 ni ayirish.

$$x^{2}-6x+1$$