2(m+1)x=3(m+1)(m-2) eching

$$2 ( m + 1 ) x = 3 ( m + 1 ) ( m - 2 )$$

x uchun yechish (complex solution)

$$\left\{\begin{matrix}\\x=\frac{3\left(m-2\right)}{2}\text{, }&\text{unconditionally}\\x\in \mathrm{C}\text{, }&m=-1\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 ga m+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(2m+2\right)x=3\left(m+1\right)\left(m-2\right)$$

2m+2 ga x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2mx+2x=3\left(m+1\right)\left(m-2\right)$$

3 ga m+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2mx+2x=\left(3m+3\right)\left(m-2\right)$$

3m+3 ga m-2 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2mx+2x=3m^{2}-3m-6$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(2m+2\right)x=3m^{2}-3m-6$$

Ikki tarafini 2m+2 ga bo‘ling.

$$\frac{\left(2m+2\right)x}{2m+2}=\frac{3\left(m-2\right)\left(m+1\right)}{2m+2}$$

2m+2 ga bo'lish 2m+2 ga ko'paytirishni bekor qiladi.

$$x=\frac{3\left(m-2\right)\left(m+1\right)}{2m+2}$$

3\left(-2+m\right)\left(1+m\right) ni 2m+2 ga bo'lish.

$$x=\frac{3m}{2}-3$$

x uchun yechish

$$\left\{\begin{matrix}\\x=\frac{3\left(m-2\right)}{2}\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&m=-1\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 ga m+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(2m+2\right)x=3\left(m+1\right)\left(m-2\right)$$

2m+2 ga x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2mx+2x=3\left(m+1\right)\left(m-2\right)$$

3 ga m+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2mx+2x=\left(3m+3\right)\left(m-2\right)$$

3m+3 ga m-2 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$2mx+2x=3m^{2}-3m-6$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(2m+2\right)x=3m^{2}-3m-6$$

Ikki tarafini 2m+2 ga bo‘ling.

$$\frac{\left(2m+2\right)x}{2m+2}=\frac{3\left(m-2\right)\left(m+1\right)}{2m+2}$$

2m+2 ga bo'lish 2m+2 ga ko'paytirishni bekor qiladi.

$$x=\frac{3\left(m-2\right)\left(m+1\right)}{2m+2}$$

3\left(-2+m\right)\left(1+m\right) ni 2m+2 ga bo'lish.

$$x=\frac{3m}{2}-3$$

m uchun yechish

$$m=\frac{2\left(x+3\right)}{3}$$

$$m=-1$$