2(x/4+4)-4(x/2+2)=8-2x eching

$$2 ( \frac { x } { 4 } + 4 ) - 4 ( \frac { x } { 2 } + 2 ) = 8 - 2 x$$

x uchun yechish

$$x=16$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 4 ga, 4,2 ning eng kichik karralisiga ko‘paytiring.

$$8\left(\frac{x}{4}+4\right)-16\left(\frac{x}{2}+2\right)=32-8x$$

8 ga \frac{x}{4}+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$8\times \frac{x}{4}+32-16\left(\frac{x}{2}+2\right)=32-8x$$

8 va 4 ichida eng katta umumiy 4 faktorini bekor qiling.

$$2x+32-16\left(\frac{x}{2}+2\right)=32-8x$$

8x ni ikki tarafga qo’shing.

$$2x+32-16\left(\frac{x}{2}+2\right)+8x=32$$

Tenglamaning ikkala tarafini 2 ga ko'paytirish.

$$2\left(2x+32-16\left(\frac{x}{2}+2\right)\right)+16x=64$$

Tenglamaning ikkala tarafini 2 ga ko'paytirish.

$$4\left(2x+32-16\left(\frac{x}{2}+2\right)\right)+32x=128$$

-16 ga \frac{x}{2}+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4\left(2x+32-16\times \frac{x}{2}-32\right)+32x=128$$

16 va 2 ichida eng katta umumiy 2 faktorini bekor qiling.

$$4\left(2x+32-8x-32\right)+32x=128$$

-6x ni olish uchun 2x va -8x ni birlashtirish.

$$4\left(-6x+32-32\right)+32x=128$$

0 olish uchun 32 dan 32 ni ayirish.

$$4\left(-6\right)x+32x=128$$

-24 hosil qilish uchun 4 va -6 ni ko'paytirish.

$$-24x+32x=128$$

8x ni olish uchun -24x va 32x ni birlashtirish.

$$8x=128$$

Ikki tarafini 8 ga bo‘ling.

$$x=\frac{128}{8}$$

16 ni olish uchun 128 ni 8 ga bo‘ling.

$$x=16$$