2x^2-x-1=x^2-5x-(-1-x^2) eching

$$2 { x }^{ 2 } -x-1= { x }^{ 2 } -5x-(-1- { x }^{ 2 } )$$

x uchun yechish

$$x=\frac{1}{2}=0,5$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-1-x^{2} teskarisini topish uchun har birining teskarisini toping.

$$2x^{2}-x-1=x^{2}-5x+1+x^{2}$$

2x^{2} ni olish uchun x^{2} va x^{2} ni birlashtirish.

$$2x^{2}-x-1=2x^{2}-5x+1$$

Ikkala tarafdan 2x^{2} ni ayirish.

$$2x^{2}-x-1-2x^{2}=-5x+1$$

0 ni olish uchun 2x^{2} va -2x^{2} ni birlashtirish.

$$-x-1=-5x+1$$

5x ni ikki tarafga qo’shing.

$$-x-1+5x=1$$

4x ni olish uchun -x va 5x ni birlashtirish.

$$4x-1=1$$

1 ni ikki tarafga qo’shing.

$$4x=1+1$$

2 olish uchun 1 va 1'ni qo'shing.

$$4x=2$$

Ikki tarafini 4 ga bo‘ling.

$$x=\frac{2}{4}$$

\frac{2}{4} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=\frac{1}{2}$$